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Advanced TypeScript: Type Inference and Advanced Types

Tutorial August 05, 2024
typescript 

let name = 'Alice'; // inferred as string
let age = 30;       // inferred as number
let isDeveloper = true; // inferred as boolean
function add(a: number, b: number) {
  return a + b; // inferred return type is number
}

let numbers = [1, 2, 3]; // inferred as number[]

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