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Tutorial
typescript

Advanced TypeScript: Type Inference and Advanced Types

interface Person {
  name: string;
  age: number;
}

interface Employee {
  employeeId: number;
}

type EmployeePerson = Person & Employee;

const john: EmployeePerson = {
  name: 'John Doe',
  age: 35,
  employeeId: 1234
};
function printId(id: number | string) {
  console.log('ID:', id);
}

printId(101);
printId('ABC123');

Aug 05, 2024
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