Regex Development Tutorials, Guides & Insights

matches = re.findall(r'\d+', 'There are 12 apples and 5 oranges')
print(matches)  # Output: ['12', '5']

matches = re.finditer(r'\d+', 'There are 12 apples and 5 oranges')
for match in matches:
    print(match.group())  # Output: 12 5

result = re.sub(r'\d+', '#', 'There are 12 apples and 5 oranges')
print(result)  # Output: There are # apples and # oranges

result, num_subs = re.subn(r'\d+', '#', 'There are 12 apples and 5 oranges')
print(result, num_subs)  # Output: There are # apples and # oranges 2