DeveloperBreeze

PHP File Upload

// File Upload PHP Script

$targetDir = 'uploads/';
$targetFile = $targetDir . basename($_FILES['file']['name']);

if (move_uploaded_file($_FILES['file']['tmp_name'], $targetFile)) {
    echo 'File uploaded successfully.';
} else {
    echo 'Error uploading file.';
}

Related Posts

More content you might like

Code
javascript

Dynamic and Responsive DataTable with Server-Side Processing and Custom Styling

  • language.emptyTable: Custom message displayed when no data is available.
  • initComplete: Adds custom classes to dropdowns and inputs in the DataTables UI for consistent styling.

Oct 24, 2024
Read More
Tutorial
php

Handling HTTP Requests and Raw Responses in Laravel

Sometimes, you might receive raw responses in formats other than JSON, such as a query string or plain text. Here’s how to handle and process raw responses:

use Illuminate\Support\Facades\Http;

$response = Http::post('https://api.example.com/endpoint', [
    'key1' => 'value1',
    'key2' => 'value2',
]);

$rawResponse = $response->body(); // Get the raw response as a string
dd($rawResponse);

Oct 24, 2024
Read More
Article
javascript

20 Useful Node.js tips to improve your Node.js development skills:

No preview available for this content.

Oct 24, 2024
Read More
Tutorial
javascript

AJAX with JavaScript: A Practical Guide

  • The fetch() method returns a Promise that resolves to the Response object representing the entire HTTP response.
  • We check if the response is successful and then parse it as JSON.
  • Any errors during the request are caught and logged.

In many real-world applications, you'll need to send data to the server using POST requests. Here's how to send form data using the Fetch API.

Sep 18, 2024
Read More

Discussion 0

Please sign in to join the discussion.

No comments yet. Be the first to share your thoughts!