$jsonString = file_get_contents('data.json');
$data = json_decode($jsonString, true);
print_r($data);JSON File Reading and Decoding
Related Posts
More content you might like
Tutorial
javascript
التعامل مع JSON في JavaScript: قراءة البيانات وكتابتها
fetch('https://jsonplaceholder.typicode.com/users/1')
.then(response => response.json())
.then(data => {
console.log(data);
console.log("الاسم:", data.name);
})
.catch(error => {
console.error("حدث خطأ:", error);
});في هذا المثال، نستخدم fetch() لطلب بيانات من API، ثم نستخدم response.json() لتحويل الاستجابة إلى كائن JSON يمكننا التعامل معه.
Sep 26, 2024
Read More Tutorial
javascript
AJAX with JavaScript: A Practical Guide
In this guide, we'll explore how AJAX works, the basics of making AJAX requests using vanilla JavaScript, and some real-world examples to help you implement AJAX in your own projects.
- Basic knowledge of HTML, CSS, and JavaScript.
- Familiarity with JSON (JavaScript Object Notation) as a format for exchanging data.
Sep 18, 2024
Read More Tutorial
go
Building a RESTful API with Go and Gorilla Mux
Add the updateBook function to main.go:
func updateBook(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Content-Type", "application/json")
params := mux.Vars(r)
for index, item := range books {
if item.ID == params["id"] {
books = append(books[:index], books[index+1:]...)
var book Book
_ = json.NewDecoder(r.Body).Decode(&book)
book.ID = params["id"]
books = append(books, book)
json.NewEncoder(w).Encode(book)
return
}
}
json.NewEncoder(w).Encode(books)
}Aug 12, 2024
Read More Code
javascript json
How to Deep Clone a JavaScript Object
No preview available for this content.
Aug 12, 2024
Read MoreDiscussion 0
Please sign in to join the discussion.
No comments yet. Be the first to share your thoughts!